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Ncert Cbse Class 8 Mathematics Solutions | Linear Equations in One Variable | NCERT Exercise 2.2 Solved (PART – I)

CBSE Mathematics Solutions Class VIII

Ncert Solutions of  8th Maths Exercise 2.2

Linear Equations in One Variable

(page 28)
Q 1: If you subtract 1/2 from a number and multiply the result by 1/2, you get 1/8. What is the number?    
Let the number be x. Then by subtracting 1/2 from x and multiplying the result by 1/2 we get, 
Ncert Cbse Class 8 Mathematics Solutions | Linear Equations in One Variable | NCERT Exercise 2.2 Solved

Q 2: The perimeter of a rectangular swimming pool is 154 m. Its length is 2m more than twice its breadth. What are the length and breadth of the pool?
Let the breadth of the swimming pool be x.
Therefore, its length = 2x + 2
Given the perimeter of the pool = 154 m.
or, 2(2x + 2 + x) = 154
or, 6x + 4 = 154
or,  x = 25m
Hence, Breadth = 25m and
Length = 2 x 25 + 2 = 52m
Q 3: The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 42/15 cm. What is the length of either of the remaining equal sides?       
Let the length of one equal side of the isosceles triangle be x.
Base of the isosceles triangle = 4/3cm (given)
Ncert Cbse Class 8 Mathematics Solutions | Linear Equations in One Variable | NCERT Exercise 2.2 Solved

Q 4: Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
Let one number be x and so, the other number is (x + 15).
or,  x + x + 15 = 95 (sum of the numbers given).
or, x = 40 (and the other number is 40 + 15 = 55)
So, the numbers are 40 and 55 respectively.
Q 5: Two numbers are in the ratio 5 : 3. If they differ by 18, what are the numbers?
Let the numbers are x and y
Under the given conditions:
NCERT Class 8 Math Solution Ex 2.2

Q 6: Three consecutive integers add up to 51. What are these integers?   
Let the three consecutive integers be x, (x + 1) and (x + 2).
According to the given condition,
x + (x + 1) + (x + 2) = 51
or, x = 16
Therefore the three consecutive integers are 16, 17 and 18 respectively.
Q 7: The sum of three consecutive multiples of 8 is 888. Find the multiples.
Let the first multiple of 8 be 8x.
Second multiple be 8x + 8.
Third multiple be 8x + 8 + 8 = 8x + 16.
According to the given condition,
8x + 8x + 8 + 8x + 16 = 888
or, 24x = 864
or, x = 36.
Hence, 8x = 8 x 36 = 288,
8x + 8 = 296,
8x + 16 = 304.
So, the numbers will be 288, 296 and 304.
Q 8: Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 74. Find these numbers.  
Solution: (Taking hint from Q7 solution do it yourself.)


SHIKSHA said...

Very helpful.

nick said...

Linear equations: no brain required
Quadratic equations: still a bit easy. Complete the square or use quadratic formula and you’re done!
Cubic equations: a bit hard. Most people need special formulas.
quartic equations: very hard
anything beyond quartic: scream for your mom and panic

harjay patel said...

very healpfull

Vaibhav Bhatia said...

where r answers of rest questions

Vaibhav, answers u r looking for will be loaded here soon. Pl be in touch. Tnx 4 writing. Happy surfing and Happy searching !!


good it is very useful now if i show the correct sums teacher will say good

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