__CBSE Mathematics Class VIII __

**Ncert Solutions of Maths ****Exercise 2.2 **

*Linear Equations in One Variable*

*(page 28)*

Q1: If you subtract 1/2 from a number and multiply the result by 1/2, you get 1/8. What is the number?

Solution:

Let the number be *x*. Then by subtracting 1/2 from *x* and multiplying the result by 1/2 we get,

Q2: The perimeter of a rectangular swimming pool is 154 m. Its length is 2m more than twice its breadth. What are the length and breadth of the pool?

Solution:

Let the breadth of the swimming pool be *x*.

Therefore, its length = 2*x* + 2

Given the perimeter of the pool = 154 m.

or, 2(2*x* + 2 + *x*) = 154

or, 6*x* + 4 = 154

or, *x* = 25m

Hence, Breadth = 25m and

Length = 2 x 25 + 2 = 52m

Q3: The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4^{2/15} cm. What is the length of either of the remaining equal sides?

Solution:

Let the length of one equal side of the isosceles triangle be *x*.

Base of the isosceles triangle = 4/3cm (given)

Q4: Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.

Solution:

Let one number be *x* and so, the other number is (*x* + 15).

or, *x* + *x* + 15 = 95 (sum of the numbers given).

or, *x* = 40 (and the other number is 40 + 15 = 55)

So, the numbers are 40 and 55 respectively.

Q5: Two numbers are in the ratio 5 : 3. If they differ by 18, what are the numbers?

Solution:

Let the numbers are *x* and y

Under the given conditions:

Q6: Three consecutive integers add up to 51. What are these integers?

Solution:

Let the three consecutive integers be *x, *(*x* + 1) and (*x* + 2).

According to the given condition,

*x *+* *(*x* + 1) + (*x* + 2) = 51

or, *x* = 16

Therefore the three consecutive integers are 16, 17 and 18 respectively.

Q7: The sum of three consecutive multiples of 8 is 888. Find the multiples.

Solution:

Let the first multiple of 8 be 8*x*.

Second multiple be 8*x* + 8.

Third multiple be 8*x* + 8 + 8 = 8*x* + 16.

According to the given condition,

8*x* + 8*x* + 8 + 8*x* + 16 = 888

or, 24*x* = 864

or, *x* = 36.

Hence, 8*x* = 8 x 36 = 288,

8*x* + 8 = 296,

8*x* + 16 = 304.

So, the numbers will be 288, 296 and 304.

Q8: Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 74. Find these numbers.

Solution: (Taking hint from Q7 solution do it yourself.)

__Ncert Cbse Class 8 Mathematics Solutions | Linear Equations in One Variable | NCERT Exercise 2.2 Solved (PART – II)__** [View solutions of rest questions]**

## 6 comments:

Very helpful.

Linear equations: no brain required

Quadratic equations: still a bit easy. Complete the square or use quadratic formula and you’re done!

Cubic equations: a bit hard. Most people need special formulas.

quartic equations: very hard

anything beyond quartic: scream for your mom and panic

very healpfull

where r answers of rest questions

Vaibhav, answers u r looking for will be loaded here soon. Pl be in touch. Tnx 4 writing. Happy surfing and Happy searching !!

good it is very useful now if i show the correct sums teacher will say good

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