Polynomials - Class 9 CBSE Mathematics Guide | NCERT Solutions Math Exercise 2.2

Class 9 CBSE Mathematics Guide

POLYNOMIALS

NCERT Solutions of Math Exercise 2.2

Question.1: Find the value of the polynomial at 5x - 4x2 + 3
(i) x = 0   (ii) x = −1   (iii) x = 2
Solution:
p(x) = 5x - 4x2 + 3
(i) At x = 0, p(0) = 5 x 0 - 4 x 02 + 3 = 3 Ans.
(ii) At x = –1, p(–1) = 5 x (–1) - 4 x (–1)2 + 3 = – 6 Ans.
(iii) At x = 2, p(2) = 5 x 2 - 4 x 22 + 3 = – 3 Ans.

Question.2: Find p(0), p(1) and p(2) for each of the following polynomials:
(i) p(y) = y2y + 1   (ii) p(t) = 2 + t + 2t2t3
(iii) p(x) = x3   (iv) p(x) = (x − 1) (x + 1)
Solution:
Question.3: Verify whether the following are zeroes of the polynomial, indicated against them.
Solution:
Question.4: Find the zero of the polynomial in each of the following cases:
(i) p(x) = x + 5 (ii) p(x) = x − 5 (iii) p(x) = 2x + 5
(iv) p(x) = 3x − 2 (v) p(x) = 3x (vi) p(x) = ax, a ≠ 0
(vii) p(x) = cx + d, c ≠ 0, c, are real numbers.
Solution:


We know that zero of a polynomial is that value of the variable at which the value of the polynomial is obtained as 0.




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