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**Class
9 CBSE Mathematics Guide**

**POLYNOMIALS**

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*NCERT
Solutions of Math Exercise 2.2 *

Question.1: Find the
value of the polynomial

**at 5***x*- 4*x*^{2}+ 3
(i)

*x*= 0 (ii)*x*= −1 (iii)*x*= 2**Solution:**

p(

*x*) = 5*x*- 4*x*^{2}+ 3
(i) At

*x*= 0, p(0) = 5 x 0 - 4 x 0^{2}+ 3 = 3 Ans.
(ii) At

*x*= –1, p(–1) = 5 x (–1) - 4 x (–1)^{2}+ 3 = – 6 Ans.
(iii) At

*x*= 2, p(2) = 5 x 2 - 4 x 2^{2}+ 3 = – 3 Ans.
Question.2: Find

*p*(0),*p*(1) and*p*(2) for each of the following polynomials:
(i)

*p*(*y*) =*y*^{2}−*y*+ 1 (ii)*p*(*t*) = 2 +*t*+ 2*t*^{2}−*t*^{3 }
(iii)

*p*(*x*) =*x*^{3}(iv)*p*(*x*) = (*x*− 1) (*x*+ 1)**Solution:**

Question.3: Verify
whether the following are zeroes of the polynomial, indicated against them.

**Solution:**

Question.4: Find the zero
of the polynomial in each of the following cases:

(i)

*p*(*x*) =*x*+ 5 (ii)*p*(*x*) =*x*− 5 (iii)*p*(*x*) = 2*x*+ 5
(iv)

*p*(*x*) = 3*x*− 2 (v)*p*(*x*) = 3*x*(vi)*p*(*x*) =*ax*,*a*≠ 0
(vii)

*p*(*x*) =*cx*+*d*,*c*≠ 0,*c*, are real numbers.**Solution:**

We know that zero of a polynomial is
that value of the variable at which the value of the polynomial is obtained as
0.